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a ship approaches a cliff its siren is sounded again and the echo is heard in the ship after 12seconds, 2.1 minutes later the siren was sounded again and the echo was heard 8seconds later . If the speed of sound in air is 340m/s calculate the velocity at which the ship was approaching the cliff​

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Bonjour

The time taken for the sound to travel from the ship to the cliff and back is 12 seconds. Since we only need the one-way distance, we'll divide this time by 2 so 6 seconds

The distance travelled by the sound is  d₁ = 340 m/s × 6 s = 2040 meters

During the second instance, the time taken for the sound to travel from the ship to the cliff and back is 8 seconds. So a one way in 4 seconds

The distance travelled by the sound is  d₂ = 340 m/s × 4 s = 1360 meters

During the time interval of 2.1 minutes (or 126 seconds), the ship approaches the cliff, reducing the distance between them. The change in distance is 2040-1360 = 680 meters

The velocity of the ship is 680 meters / 126 seconds = 5.4 m/s