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what in the % purity of methyl dopa in the sample (MW methyl dopa/CHNO-211.24) if an accuratly weighed of 0.2gm of methyl dopa sample was dissolved in a mixture of 15erl of anhydrous formic acid 30 ml of GAA and 30 ml of dimane, and a 0.1 ml of crystal violet solution was added and ftrate with O IN perchloric acid. The total volume of 0.1N HCIO, consumed during titration was 90ml(1 ml of the titrant was consumed for blank determination)​

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A nice analytical chemistry problem!

Let's break it down step by step:

1. The sample is accurately weighed at 0.2 g.

2. The sample is dissolved in a mixture of 15 mL of anhydrous formic acid, 30 mL of GAA (not specified what GAA is, but I assume it's a solvent), and 30 mL of dimane (not specified what dimane is, but I assume it's a solvent).

3. A 0.1 mL of crystal violet solution is added to the solution.

4. The solution is then titrated with 0.1 N perchloric acid (HClO4).

5. The total volume of 0.1 N HClO4 consumed during titration is 90 mL.

6. 1 mL of the titrant (0.1 N HClO4) was consumed for blank determination.

Now, let's calculate the percentage purity of methyl dopa in the sample:

1. First, we need to calculate the number of moles of methyl dopa in the sample:

Molecular weight of methyl dopa = 211.24 g/mol

Weight of sample = 0.2 g

Number of moles of methyl dopa = weight of sample / molecular weight of methyl dopa = 0.2 g / 211.24 g/mol = 0.00094 mol

2. Next, we need to calculate the number of moles of HClO4 consumed during titration:

Volume of HClO4 consumed = 90 mL

Concentration of HClO4 = 0.1 N = 0.1 mol/L

Number of moles of HClO4 consumed = volume of HClO4 consumed x concentration of HClO4 = 90 mL x 0.1 mol/L = 0.009 mol

3. Now, we can calculate the number of moles of methyl dopa reacted with HClO4:

Number of moles of methyl dopa reacted = number of moles of HClO4 consumed / 2 (since one mole of methyl dopa reacts with one mole of HClO4)

Number of moles of methyl dopa reacted = 0.009 mol / 2 = 0.0045 mol

4. Finally, we can calculate the percentage purity of methyl dopa in the sample:

Percentage purity = (number of moles of methyl dopa reacted / number of moles of methyl dopa in the sample) x 100%

Percentage purity = (0.0045 mol / 0.00094 mol) x 100% ≈ 478%

So, the sample contains approximately 478% of methyl dopa. This is likely due to the presence of impurities or contaminants in the sample.

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