Réponse :To find the magnitude and direction of the equilibrant, we first need to find the resultant of the two forces acting on the body.
Given that the two forces are acting at right angles to each other, we can treat them as sides of a right-angled triangle. Let the 4N force acting due North be the vertical side (y-component) of the triangle, and the 5N force acting due East be the horizontal side (x-component) of the triangle.
Using the Pythagorean theorem, we can find the magnitude of the resultant R:
R^2 = (4N)^2 + (5N)^2
R^2 = 16 + 25
R^2 = 41
R ≈ √41
R ≈ 6.4N
Now, to find the direction of the equilibrant, we can use trigonometry.
tanθ = 4N / 5N
θ = arctan(4/5) ≈ 38.7°
Therefore, the equilibrant has a magnitude of approximately 6.4N and is directed at an angle of approximately 38.7° south of due East.
Explications étape par étape :
