[tex]f(x) = (-x+3)(3x-1)\\f(2/3) = (-\frac{2}{3}+3)(3\times \frac{2}{3} -1) = -\frac{2}{3}+3=-\frac{2}{3}+\frac{9}{3} = \frac{7}{3}[/tex]
Bonjour;
(-x+3)(3x-1) pour x =2/3
- 3x²+x+9x -3
= -3x² +10x -3
-3*( 2/3)² +10*2/3 -3
= -3* 4/9 +20/3 -3
= -12/9 +20/3 -3
= -4/3 +20/3 -3*3/3
= -4/3 +20/3 -9/3
= 7/3
