bonjour
selon le th de Pythagore
AC² = AB² + BC²
(5 x + 3 )² = ( 3 x + 5 )² + 4 ²
25 x² + 30 x + 9 = 9 x² + 30 x + 25 + 16
25 x² - 9 x² + 30 x - 30 x = 25 + 16 - 9
16 x² = 32
x² = 2
x = √2
( 5 √2 + 3 )² = 4² + (3 √2 + 5 )²
50 + 9 = 16 + 18 + 25
59 = 59
