Réponse:
arithmétique, on calcule
�
�
+
1
−
�
�
W
n+1
−W
n
:
�
�
+
1
−
�
�
=
5
�
�
+
1
−
5
�
�
=
5
10
�
�
10
+
�
�
−
5
�
�
=
5
(
10
+
�
�
)
10
�
�
−
5
�
�
=
5
(
10
+
�
�
)
−
5
×
10
10
�
�
=
5
�
�
10
�
�
=
1
2
W
n+1
−W
n
=
u
n+1
5
−
u
n
5
=
10+u
n
10u
n
5
−
u
n
5
=
10u
n
5(10+u
n
)
−
u
n
5
=
10u
n
5(10+u
n
)−5×10
=
10u
n
5u
n
=
2
1
.
Donc
(
�
�
)
(W
n
) est une suite arithmétique de raison
�
=
1
2
r=
2
1
et de premier terme
�
0
=
5
�
0
=
5
5
=
1
W
0
=
u
0
5
=
5
5
=1 .
3)
�
�
=
1
+
1
2
�
W
n
=1+
2
1
n .
4)
�
�
=
5
�
�
⇔
�
�
=
5
�
�
=
5
1
+
1
2
�
W
n
=
u
n
5
⇔u
n
=
W
n
6
=
1+
2
1
n
5
.