To find the length, breadth, and perimeter of a rectangle with an area of 225 square centimeters, we first need to determine the dimensions of the rectangle.
Let's denote:
- Length as L
- Breadth as B
Given that the area (A) of the rectangle is 225 square centimeters, we have the equation:
\[ A = L \times B \]
Substituting the given area value, we get:
\[ 225 = L \times B \]
We can choose various combinations of \(L\) and \(B\) that multiply to 225. For example, if \(L = 15\) and \(B = 15\), or \(L = 25\) and \(B = 9\), or \(L = 45\) and \(B = 5\), etc.
To find the perimeter (P) of the rectangle, we use the formula:
\[ P = 2(L + B) \]
Now, let's calculate the length, breadth, and perimeter for one of the possible combinations.
Let's say \(L = 15\) and \(B = 15\):
\[ P = 2(15 + 15) = 2 \times 30 = 60 \text{ centimeters} \]
For a square, since all sides are equal, we simply need to find the side length. Given that the area of the square is 225 square centimeters, the formula for the area (A) of a square is:
\[ A = side^2 \]
Substituting the given area value, we get:
\[ 225 = side^2 \]
Taking the square root of both sides, we find:
\[ side = \sqrt{225} = 15 \text{ centimeters} \]
For a square, the perimeter (P) is:
\[ P = 4 \times \text{side} = 4 \times 15 = 60 \text{ centimeters} \]
So, for a rectangle with an area of 225 square centimeters, one possible set of dimensions could be 15 centimeters by 15 centimeters, with a perimeter of 60 centimeters. Similarly, for a square with the same area, each side would measure 15 centimeters, also resulting in a perimeter of 60 centimeters.
