Réponse :
Bonjour
1) f'(x) = 4x - 9 - 1/x² = (4x³ - 9x² - 1) / x²
2) g'(x) = 3x² - 3/x² = (3x⁴ - 3) / x²
3) h'(x) = [(16x + 5)x - (8x² + 5x - 1)] / x² = (16x² + 5x - 8x² + 5x +1)/ x²
h'(x) = (8x² + 1) / x²
4) k'(x) = [(-15x² +6x)x - (-5x³ + 3x² + 4)] / x²
k'(x) = (-15x³ + 6x² + 5x³ - 3x² - 4) / x²
k'(x) = (-10x³ + 3x² - 4) / x²
